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2.5x^2=5.5-2.3x
We move all terms to the left:
2.5x^2-(5.5-2.3x)=0
We add all the numbers together, and all the variables
2.5x^2-(-2.3x+5.5)=0
We get rid of parentheses
2.5x^2+2.3x-5.5=0
a = 2.5; b = 2.3; c = -5.5;
Δ = b2-4ac
Δ = 2.32-4·2.5·(-5.5)
Δ = 60.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.3)-\sqrt{60.29}}{2*2.5}=\frac{-2.3-\sqrt{60.29}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.3)+\sqrt{60.29}}{2*2.5}=\frac{-2.3+\sqrt{60.29}}{5} $
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